∫π/6π/3 Sin3xSin3x+Cos3x dx=

$\int_{π / 6}^{π / 3} \frac{{Sin}^{3} x}{{Sin}^{3} x + {Cos}^{3} x} d x =$

A
$\frac{π}{16}$
B
$\frac{π}{12}$
C
$\frac{π}{2}$
D
$2 π$

Solution:

$\int_{π / 6}^{π / 3} \frac{S i n^{3} x}{S i n^{3} x + C o s^{3} x} d x = \frac{\frac{π}{3} - \frac{π}{6}}{2} = \frac{π}{12}$

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