A chord of a circle of radius 10cm subtends a right angle at the centre. ____ is the area of the major sector. Chapter/Topic:  circles

# A chord of a circle of radius 10cm subtends a right angle at the centre. ____ is the area of the major sector. Chapter/Topic:  circles

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### Solution:

In the mentioned circle,
O is the centre and AO =BO = Radius = 10 cm
AB is a chord which subtents 90o at centre O, i.e., AOB=${{90}}^{{0}}$
The angle at the sector is 90 degrees so the area of the sector is equal to the quadrant of the circle.
Area of Major sector = Area of circle - Area of Sector AOB
Area of sector = Area of circle/4
= (π×10×10)−
=314−78.5
=235.5 ${{\mathit{cm}}}^{{2}}$
Hence, 235.5 ${{\mathit{cm}}}^{{2}}$ is the area of the major sector.

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