A chord of a circle of radius 10cm subtends a right angle at the centre. ____ is the area of the major sector. Chapter/Topic: circles - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

Solution:

In the mentioned circle,

O is the centre and AO =BO = Radius = 10 cm
AB is a chord which subtents 90o at centre O, i.e., ⦟AOB=

90^{0}

The angle at the sector is 90 degrees so the area of the sector is equal to the quadrant of the circle.
Area of Major sector = Area of circle - Area of Sector AOB
Area of sector = Area of circle/4
= (π×10×10)−

\frac{(π \times 10 \times 10 ​)}{4}

=314−78.5
=235.5

{cm}^{2}

Hence, 235.5

{cm}^{2}

is the area of the major sector.

Solution:

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