Solution:In the mentioned circle,
O is the centre and AO =BO = Radius = 10 cm
AB is a chord which subtents 90o at centre O, i.e., ⦟AOB=
The angle at the sector is 90 degrees so the area of the sector is equal to the quadrant of the circle.
Area of Major sector = Area of circle - Area of Sector AOB
Area of sector = Area of circle/4
Hence, 235.5 is the area of the major sector.