MathematicsA die is thrown once. Find the probability of getting a composite number.

A die is thrown once. Find the probability of getting a composite number.


  1. A
    13
  2. B
    53
  3. C
    23
  4. D
    12 

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    Solution:

    Given that a die is thrown once.
    We know that the probability is given as the ratio of the number of favorable outcomes with the total number of possible outcomes.
    P(E)=Number of favourable outcomes n(E)Total possible outcomes n(S)
    On the throw of a dice there are six possible outcomes.
    S={1,2,3,4,5,6}
    n(S)=6
    As composite numbers are those which have factors other than one and itself.
    So, among a total of six outcomes, favourable outcomes are outcomes having composite numbers 1 is neither a prime number nor a composite number.
    Let E be the event of getting a composite number.
    Favourable outcomes are E={2,4,6}.
    n(E)=3
    The probability of getting composite number in one throw is,
    P(E)=Number of favourable outcomes n(E)Total number of outcomes n(S)
    P(E)=26
    P(E)=13
    Thus, the probability of getting composite number is 13.
    Hence, option 1 is correct.
     
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