### Solution:

The lady has ten friends. Two of these friends will not agree to go to the party together. So, let us consider the following case: neither of the two friends will attend the party. So, the number of ways six guests can be invited in this case will be equal to the number of ways to choose 6 friends out of the remaining 8 friends.${C}_{6}^{8}=28$

Therefore, there are 28 ways to invite 6 friends when the two friends will not be going to the party. Consider the next case, which is that one of the two friends decides to attend the party. So, if either of the two decide to attend the party, then the rest 5 guests will be chosen from the remaining 8 friends. Therefore, if one friend decides to attend the party, the number of ways to invite the other 5 guests is ${C}_{5}^{8}$. Similarly, if the other friend decides to attend the party, the number of ways to invite the other 5 guests is ${C}_{5}^{8}$.

Therefore, the number of ways to invite the guests if either, if the two friends is going to the party, is ${2\times C}_{5}^{8}$

= 112

Therefore, the total number of ways to invite six guests out of ten with the given condition is 28+112 =140.

Hence, Option (2) is the correct answer.