MathematicsA potential difference of 4V is applied to two resistors of 6 ohms and 2 ohms connected in series. Find the combined resistance in ohms, the current flowing in the circuit and the potential difference across the 6 ohms resistor.

A potential difference of 4V is applied to two resistors of 6 ohms and 2 ohms connected in series. Find the combined resistance in ohms, the current flowing in the circuit and the potential difference across the 6 ohms resistor.


  1. A
    4 ohms, 0.5 A, 6V
  2. B
    8 ohms, 10 A, 3V
  3. C
    4 ohms, 10 A, 6V
  4. D
    8 ohms, 0.5 A, 3V 

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    Solution:

    Concept: When resistors are daisy chained together in a single line and a common current flows through them, they are said to be connected in series.
    Individual resistors in a series resistor network add up to give the series combination's equivalent resistance. A series circuit's resistors can be swapped out without affecting the total resistance, current, or power delivered to each resistor or the circuit.
    We can calculate the combined resistance by
    Req = R1 + R2
    ⇒Req = 6 + 2
    ∴Req = 8 ohms
    The combined resistance is 8 ohms
    Resistors in series carry the same current, but their individual resistance values cause different voltage drops across each resistor, according to Ohm's Law (V = IR) (V = IR)
    p.d. applied to two 6 ohm and 2 ohm resistors = 4V
    V = IR
    ⇒I = V/R
    ⇒I = 4/8
    ∴I = 0.5A
    The current flowing is 0.5A
    The potential difference across 6 ohms(r = 6 ohms) can be calculated as,

    I = 0.5A
    ⇒V = IR
    ⇒V = 0.5×6
    ∴V = 3V 
    So, the potential difference across 6 ohms is 3V.

    Hence, the answer is option 4.
     
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