A  variable  X takes values 0, 2, 4, 6   ….,2n with frequencie   nC0,nC1,nC2,…,nCn   respectively. If the mean of this data is 7282n,   then   n is equal  to

 A  variable  X takes values 0, 2, 4, 6   ….,2n with frequencie   nC0,nC1,nC2,,nCn   respectively. If the mean of this data is 7282n,   then   n is equal  to

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    Solution:

    It is given that  

    0nC0+2nC1+4nC2++2nnCn nC0+nC1+nC2++nCn=7282nr=1nnCr2rr=1nnCr=7282n

    r=0nnCr2r12n=7282n(1+2)n12n=7282n3n1=7293n=7293n=36n=6

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