Among 15 players,8 are batsmen and 7 are bowlers. The probability that a team is chosen of 6 batsmen and 5 bowlers, is

# Among 15 players,8 are batsmen and 7 are bowlers. The probability that a team is chosen of 6 batsmen and 5 bowlers, is

1. A

2. B

3. C

$\frac{15}{28}$

4. D

None of these

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### Solution:

Total number of ways of selecting 11 players  ${=}^{15}{C}_{11}$
Favorable cases ${=}^{8}{\mathrm{C}}_{6}{×}^{7}{\mathrm{C}}_{5}$
Required probability

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