An experiment yields 3 mutually exclusive and exhaustive events A, B and C. If P(A) = 2P(B) = 3P(C), then P(A) is equal to

A
1/11
B
2/11
C
3/11
D
6/11

Solution:

Clearly,

$\begin{array}{l} \Rightarrow P (A \cup B \cup C) = 1 \\ \Rightarrow P (A) + P (B) + P (C) = 1 \\ \Rightarrow P (A) + \frac{1}{2} P (A) + \frac{1}{3} P (A) = 1 \\ \Rightarrow \frac{11}{6} P (A) = 1 \\ \Rightarrow P (A) = \frac{6}{11} \end{array}$

Related content

Appreciation Words

Wave Optics Mind Map

Alternating Current Mind Map for Class 12, JEE & NEET

Paramedical Courses After Class 10

Top Courses After 12th Science with PCM, PCB and PCMB

Subject Change Application in School and College

CBSE Class 10 Result 2024: Is the Release Date Early? Check Expected Schedule

Mizoram NEET Merit List 2023

Government Jobs After 12th Arts Stream

Chhattisgarh NEET UG Merit List 2023