MathematicsAn integer is chosen at random between 1 and 100. Find the probability that it is divisible by 8 and not divisible by 8.

An integer is chosen at random between 1 and 100. Find the probability that it is divisible by 8 and not divisible by 8.


  1. A
    6 49 , 43 49  
  2. B
    6 50 , 43 50  
  3. C
    5 49 , 43 49  
  4. D
    6 49 , 5 49   

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    Solution:

    Given, an integer is chosen at random between 1 and 100.
    P(E)= n(E) n(S)  
    To find the probability that the number is divisible by 8  .
    The numbers between 1   and 100 which are divisible by 8   are {8,16,24,32,40,48,56,64,72,80,88,96}   Total number of numbers which are divisible by 8 =12   Total number of numbers = 98 (excluding 1 and 100)
    Probability of choosing a number that is divisible by 8
    = 12 98 = 6 49    Total number of numbers which are not divisible by 8 = 86.
    Probability of choosing a number that is not divisible by 8= 86 98    = 43 49  
    The probability of choosing a number which is divisible by 8   is 6 49   and the probability of choosing a number which is not divisible by 8   is 43 49   .
    Hence, the correct option is 1.
     
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