### Solution:

Given, an integer is chosen at random between 1 and 100.$\n \n P(E)=\n \n n(E)\n \n n(S)\n \n \n $

To find the probability that the number is divisible by $\n 8\n $ .

The numbers between $\n 1\n $ and 100 which are divisible by $\n 8\n $ are $\n \n {8,16,24,32,40,48,56,64,72,80,88,96}\n $ Total number of numbers which are divisible by 8 $\n \n =12\n $ Total number of numbers = 98 (excluding 1 and 100)

Probability of choosing a number that is divisible by 8

$\n \n =\n \n 12\n \n 98\n \n =\n 6\n \n 49\n \n \n $ Total number of numbers which are not divisible by 8 = 86.

Probability of choosing a number that is not divisible by $\n \n 8=\n \n 86\n \n 98\n \n \n $ $\n \n =\n \n 43\n \n 49\n \n \n $

The probability of choosing a number which is divisible by $\n 8\n $ is $\n \n \n 6\n \n 49\n \n \n $ and the probability of choosing a number which is not divisible by $\n 8\n $ is $\n \n \n \n 43\n \n 49\n \n \n $ .

Hence, the correct option is 1.