An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at random without replacement from the urn. The probability that the three balls have different colours is

An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at random without replacement from the urn. The probability that the three balls have different colours is

  1. A

    121

  2. B

    223

  3. C

    13

  4. D

    27

    Register to Get Free Mock Test and Study Material

    +91

    Verify OTP Code (required)

    I agree to the terms and conditions and privacy policy.

    Solution:

    Total number of ways of drawing three balls out of 9 is  9C3=84. 

    n(S)=84

    E= event of drawing 3 balls of different colours

    The number of ways of drawing the balls so that balls are of different colours is    3C1 4C1 2C1=(3)(4)(2)=24

    n(E)=24

      probability of the required event P(E)=2484=27

    Chat on WhatsApp Call Infinity Learn

      Register to Get Free Mock Test and Study Material

      +91

      Verify OTP Code (required)

      I agree to the terms and conditions and privacy policy.