Area of parallelogram BCEF = 40 cm2, then find the area of triangle BCE.

A
10 cm²
B
20 cm²
C
30 cm²
D
40 cm²

Solution:

Given, the area of parallelogram BCEF = 40 cm²

Since the triangle BCE and the parallelogram BCEF are on the same base and between the same parallels, therefore the area of the parallelogram BCEF is twice the area of the triangle BCE.
Therefore, the area of the triangle BCE = $\frac{1}{2}$ x area of parallelogram BCEF

= $\frac{1}{2}$ x 40

= 20 cm²

Area of parallelogram BCEF = 40 cm², then find the area of triangle BCE.

Solution:

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