At x=π2,ddxcos(sinx2)= - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

$\frac{d}{d x} [\cos (\sin x^{2})] = - \sin (\sin x^{2}) \cos x^{2} \cdot 2 x$

$Putting x = \sqrt{\frac{π}{2}}, we have$ $= - 2 \sqrt{\frac{π}{2}} \sin (\sin \frac{π}{2}) \cos \frac{π}{2} = 0, [∵ \cos \frac{π}{2} = 0]$

At $x = \sqrt{\frac{π}{2}}, \frac{d}{d x} \cos (\sin x^{2}) =$