MathematicsBox A contains 25 slips of which 19 are marked Re.1 and others are marked Rs.5 each. Box B contains 50 slips of which 45 are marked Re.1 each and others are marked Rs.13 each. Slips of both boxes are poured into a third box and reshuffled. A slip is drawn at random. From the following choices, what is the probability that it is marked other than Re.1 ?

Box A contains 25 slips of which 19 are marked Re.1 and others are marked Rs.5 each. Box B contains 50 slips of which 45 are marked Re.1 each and others are marked Rs.13 each. Slips of both boxes are poured into a third box and reshuffled. A slip is drawn at random. From the following choices, what is the probability that it is marked other than Re.1 ?


  1. A
    19 75
  2. B
    11 75
  3. C
    64 75
  4. D
    13 75  

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    Solution:

    It is given that boxes contain some slips with Re.1, Rs.5, and Rs.13.
    We have to find the probability that the marked slip is other than Re.1 .
    First we find the total number of slips.
    n(S)=25+50
    =75
    19 are marked in Box A and 45 are marked in Box B as Re.1.
    So, 19+45 =64 .
    The number of slips that are marked other than Re.1 is,
    7564=11 .
    The probability of slips that are marked other than Re.1 is,
    = 11 75 .
    The probability that slip is marked other than is 11 75 .
    Hence, option 2) is correct.
     
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