Cards bearing numbers 1,3,5,7, ..........., 35 are kept in a bag. A card is drawn at random from the bag. Find the probability of getting a card bearing an odd number. - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

A
1
B
$34$
C
$13$
D
$14$

Solution:

Given that cards bearing numbers 1,3,5,7, ..........., 35 are kept in a bag.
We have to find the probability that when a card is drawn, it is bearing an odd number.
Probability of an event E is defined as:

P (E) = \frac{Number of favorable outcomes}{Total number of possible outcomes}

Since the cards are bearing numbers 1,3,5,7 ..........., 35, therefore, the sample space are,
{1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,35}.
The total number of possible outcomes is 18.
Cards bearing odd numbers are:

1, 3, 5, 7, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35

Hence, the number of favorable outcomes is 18.
Let

E

be the event of getting a card bearing an odd number.
Now, the probability of getting a card bearing an odd number is:

P (E) = 1818 ⇒ P (E) = 1

The probability of getting a card bearing an odd number is 1.
Therefore, option 1 is correct.

Solution:

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