MathematicsChances of winning a game are 60 %. If Anil has played the game 20 times, how many times can he expect to lose?

Chances of winning a game are 60 %. If Anil has played the game 20 times, how many times can he expect to lose?


  1. A
    7
  2. B
    6
  3. C
    8
  4. D
    5 

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    Solution:

    It is given that the chances of winning a game are 60 %.
    The probability states that there cannot be a 100 percent probability of something. And probability always stays between zero and hundred.
    Probability of winning=60100
    Probability of winning=0.6
    Therefore, probability of losing a game is,
    Probability of losing=1-Probability of winning
    Probability of losing=1-0.6
    Probability of losing=0.4
    Anil played 20 games, so the number of times expected to lose =0.4×20
     Number of times expected to lose =8
    Thus, Anil expected to lose 8 games out of 20, if the chance of winning the game is 60%.
    Hence, option 3 is correct.
     
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