Solution:
We have, f(x)= x2 – p(x+1) – c=0And
= 0We have to find, c=?
f(x) = x2 – px – p – c=0
Here, a=1, b= -p, c= - p – c
= 
----- (1)
Put the values in eq (1), we get-p-c+p+1=0
-c+1=0
c= 1
Hence, Option (1) is the correct answer.
MathematicsChoose the correct option from the given below options by solving the following question: If α, β are the zeros of the polynomial f(x)=x2−p(x+1)−c=0 such that(α+1)(β+1)=0, then c=?
Choose the correct option from the given below options by solving the following question: If α, β are the zeros of the polynomial f(x)=x2−p(x+1)−c=0 such that(α+1)(β+1)=0, then c=?
And
= 0We have to find, c=?
f(x) = x2 – px – p – c=0
Here, a=1, b= -p, c= - p – c
= ----- (1)Put the values in eq (1), we get-p-c+p+1=0
-c+1=0
c= 1
Hence, Option (1) is the correct answer.
