Solution:
According to the problem, we are given that m times the term of an A.P is equal to the n times the term. We need to show that the the term of the A.P is zero.Let us assume the first term of the given A.P as a and the common difference as d.
We know that the term of the A.P is defined as Tr= a+(r-1)d .
According to the problem, we are given mTm=nTn.
⇒ m(a+(m−1)d) = n(a+(n−1)d)
⇒ ma+(−m)d = na+(−n)d
⇒ ma−na+(−m)d−(−n)d = 0
⇒ (m−n)a+(−m−+n)d = 0
⇒ (m−n)a+((m−n)(m+n)−1(m−n))d = 0
⇒ (m−n)(a+(m+n−1)d) = 0
⇒ a+(m+n−1)d = 0
⇒
So, we have found that the value of the term of the A.P is zero.
∴ We have proved that the value of the term of the A.P is zero
So, the given statement is true.