MathematicsChoose which of the following is odd one out: (i)- Camphor, Ammonium Chloride, Naphthalene balls, Sugar(ii)- Turmeric, Methyl Orange, Rose petals, Beetroot

Choose which of the following is odd one out:


(i)- Camphor, Ammonium Chloride, Naphthalene balls, Sugar


(ii)- Turmeric, Methyl Orange, Rose petals, Beetroot


  1. A
    Methyl orange is the odd one as it is not an natural indicator
  2. B
    Camphor  is the odd one as it is not a natural indicator.
  3. C
    Naphthalene balls is the odd one as it is not a natural indicator.
  4. D
    None of these 

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    Solution:

    Concept- Volatility of compounds Camphor is a translucent waxy organic chemical. If left open, it quickly evaporates (converts to a gaseous state). It's a very flammable substance.
    Ammonium chloride is an inorganic salt used in the qualitative evaluation of salts. It decomposes quickly into ammonia and hydrochloric acid.
    Naphthalene balls are a natural substance that quickly devolves into a vapour state.
    (i) Sugar is a carbonyl organic molecule with a sweet flavour. It is non-volatile in nature i.e. It is not immediately transformed to a gaseous state.
    (ii) Methyl orange
     Turmeric in basic media, it turns red, whereas in an acidic medium, it turns yellow and is a natural indicator.
    Rose petal pigments are used as a natural indicator. In an acidic media, it produces a dark red colour, whereas in a basic medium, it produces a reddish green colour.
    Beetroot is also a natural indicator and it contains anthocyanin. In an acidic medium, it turns red, while in a basic condition, it turns blue.
    Methyl orange is a chemical that has been synthesised. In an acidic medium, it turns red, while in a basic medium, it turns yellow.
    Out of all, only methyl orange is a synthetic indicator whether rest are natural indicators.
    Thus, methyl orange is the odd one out.
    Hence, the correct option is 1.
     
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