cos230°−cos260°−cos60°=

$\cos^{2} 30 ° - \cos^{2} 60 ° - \cos 60 ° =$

A
0
B
$\frac{1}{2}$
C
$\frac{3}{4}$
D
1

Solution:

\cos^{2} 30 ° - \cos^{2} 60 ° - \cos 60 ° = {(\frac{\sqrt{3}}{2})}^{2} - {(\frac{1}{2})}^{2} - \frac{1}{2}

$= \frac{3}{4} - \frac{1}{4} - \frac{1}{2} = \frac{0}{4} = 0$

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