∫cos⁡x−cos3⁡x1−cos3⁡xdx is equal to 

cosxcos3x1cos3xdx is equal to 

  1. A

    23sin1cos3/2x+C

  2. B

    32sin1cos3/2x+C

  3. C

    23cos-1cos32x+c

  4. D

    none of these

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    Solution:

    We have,  

    I=cosxcos3x1cos3xdx=cosx1cos3xsinxdx I=23112cos3/2x2dcos3/2x I=23cos1cos3/2x+C

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