Mathematicsddx[ex.sinx.ax]=

ddx[ex.sinx.ax]=

  1. A

    exax[sinx.logacosx+sinx]

  2. B

    exax[sinx.logacosxsinx]

  3. C

    exax[sinx.loga+cosxsinx]

  4. D

    exax[sinx.loga+cosx+sinx]

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    Solution:

    Hereu=ex,v=sinx,w=axBy using ddx[uvw]=uvddx(w)+vwddx(u)+uwddx(v)ddx[ex.sinx.ax]=exsinxddx(ax)+ex.axddx(sinx)+axsinxddx(ex)=exsinx(ax.loga)+exaxcosx+axsinx(ex)=exax[sinx.loga+cosx+sinx]

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