Mathematicsddx(k.xn)=

$\frac{d}{d x} (k . x^{n}) =$

A
$k . n . x^{n}$
B
$k . n . x^{n - 2}$
C
$k . n . x^{n - 3}$
D
$k . n . x^{n - 1}$

Solution:

$\frac{d}{d x} (k . x^{n}) = k . \frac{d}{d x} (x^{n}) = k . n . x^{n - 1}$

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