MathematicsddxSin−1⁡5x+121−x213=

ddxSin15x+121x213=

  1. A

    11x2

  2. B

    11+x2

  3. C

    21x2

  4. D

    0

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    Solution:

    y=Sin15x+121x213 put x= sinθ y=sin-15sinθ+12cosθ13 y=sin-1cosαsinθ+sinαcosθ , where sinα=1213,cosα=513 y=sin-1sinθ+α=θ+α y=sin-1x+α dydx=11-x2  

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