Mathematicsddx{x2+sinx+5x}=

$\frac{d}{d x} {x^{2} + \sin x + 5^{x}} =$

A
$2 x + \cos x + 5^{x}$
B
$2 x - \cos x + 5^{x} \log 5$
C
$2 x + \cos x + 5^{x} \log 5$
D
None of these

Solution:

$\begin{array}{l} \frac{d}{d x} {x^{2} + \sin x + 5^{x}} \\ = 2 x + \cos x + 5^{x} \log 5 \end{array}$

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