Mathematicsddx(x4+sinx+cosx)=

$\frac{d}{d x} (x^{4} + \sin x + \cos x) =$

A
$4 x^{3} + \cos x + \sin x$
B
$4 x^{3} - \cos x - \sin x$
C
$4 x^{3} - \cos x + \sin x$
D
$4 x^{3} + \cos x - \sin x$

Solution:

$\frac{d}{d x} (x^{4} + \sin x + \cos x) = \frac{d}{d x} (x^{4}) + \frac{d}{d x} (\sin x) + \frac{d}{d x} (\cos x) = 4 x^{3} + \cos x - \sin x$

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