∫dxcos⁡x+3sin⁡x is equal to

dxcosx+3sinx is equal to

  1. A

    12logtanx2+π12+C

  2. B

    12logtanx2π12+C

  3. C

    logtanx2+π12+C

  4. D

    logtanx2π12+C

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    Solution:

    Now,

    dxcosx+3sinx=dx212cosx+32sinx=12secxπ3dx=12logtanx2π6+π4+C=12logtanx2+π12+C

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