∫dxx2x4+13/4=Ax4+1x4B+C

dxx2x4+13/4=Ax4+1x4B+C

  1. A

    A=1,B=14

  2. B

    A=1,B=14

  3. C

    A=12,B=1

  4. D

    A=12,B=1

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    Solution:

    I=dxx2x4+13/4=dxx2x31+1x43/4

    Put1+x4=t4x5dx=dt14dtt3/4=14t3/4dt=14t1/41/4+C=1+1x41/4+C=1+x4x41/4+C

     Hence,  A=1,B=14

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