∫ex11+x2+1−2×21+x25dx

ex11+x2+12x21+x25dx

  1. A

    ex11+x2+x1+x23+C

  2. B

    ex11+x2x1+x23+C

  3. C

    ex11+x2+x1+x25+C

  4. D

    ex11x2x1+x2+C

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    Solution:

    I=ex11+x2x1+x23+x1+x23+12x21+x25dxI=ex11+x2+exx1+x23+CI=ex11+x2+x1+x23+C

     using exf(x)+f(x)dx=exf(x)+C

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