Find ‘m’ so that the roots of the equation (4+m)x2+(m+1)x+1= 0 may be equal.

# Find ‘m’ so that the roots of the equation (4+m)x2+(m+1)x+1= 0 may be equal.

1. A
5,-3
2. B
5,3
3. C
4,2
4. D
1,-5

Fill Out the Form for Expert Academic Guidance!l

+91

Live ClassesBooksTest SeriesSelf Learning

Verify OTP Code (required)

### Solution:

The given equation is:
(4+m)x2+(m+1)x+1= 0
The given equation is identical to the general form of a quadratic equation
ax2+bx+c = 0
Here we have,
a = (4+m), b = (m+1), c = 1
Putting the respective values of a,b and c we get:

Applying formula(2)i.e$.{\left(a+b\right)}^{2}={a}^{2}+2\mathit{ab}+{b}^{2}$

Let and   $x2=\frac{-m-1-\sqrt{{m}^{2}-2m-15}}{8+2m}$
According to the question we want to have x1=x2

As the denominators are same we can cancel then and write,

On cancellation of similar terms on both the sides of the equation we gwt,

Now we have two possibilities that are:
So

## Related content

 Area of Square Area of Isosceles Triangle Pythagoras Theorem Triangle Formula Perimeter of Triangle Formula Area Formulae Volume of Cone Formula Matrices and Determinants_mathematics Critical Points Solved Examples Type of relations_mathematics

+91

Live ClassesBooksTest SeriesSelf Learning

Verify OTP Code (required)