MathematicsFind the coefficient of x2 in the following polynomial (2x-5)2×2-3x+1.

Find the coefficient of x2 in the following polynomial (2x-5)2x2-3x+1.


  1. A
    16
  2. B
    4
  3. C
    -16
  4. D
    -15 

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    Solution:

    The given expression is (2x-5)2x2-3x+1.
    We know that the coefficient of xm  in axm+bx+c is a.
    Therefore, write the expression (2x-5)2x2-3x+1 in polynomial form,
    2x-52x2-3x+1
    2x×2x2+2x×-3x+2x×1+(-5)×2x2+(-5)×-2x+(-5)×1
    4x3-6x2+2x-10x2+2x-5
    4x3-16x2+4x-5
    Therefore, the coefficient of x2 in 4x3-16x2+4x-5 is -16.
    Hence, option 3 is  correct.
     
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