Find the number of ways in which 8 different flowers can be strung to form a garland so that 4 particular flowers are never separated

A
596
B
288
C
36
D
24

Solution:

Considering 4 particular flowers as one flower we have five flowers which can be strung to form a garland in $\frac{4!}{2}$ ways. But 4 particular flowers can be arranged in 4! Ways

Required number of ways $= \frac{4!}{2!} \times 4! = \frac{576}{2} = 288$

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