Solution:
Height of cone & cylinder ,h =2.4 cmRadius of cone and cylinder , r= 0.7 cm
Total surface area of remaining solid = curved surface area of cylinder +area of base +curved surface area of cone Total surface area of remaining Solid = 2πrh +πr2+πrl
= 2*22/7(0.7)*2.4+22/7*(0.7)2+
= 22/7*(0.7)*√(0.7)2+ (2.4)2 =10.55 cm2 +1053 cm 2+ 22/7*0.7*2.5
=10.55 cm2 + 1.53 cm2+ 5.49 cm2 T..a of remaining solid = 17.57 cm2 Thus option (b) is correct .
