MathematicsGiven y=a(x−2)(x+4). In the given quadratic equation, aa is a nonzero constant. The graph of the equation in the xy-plane is a parabola with vertex (c,d). Which of the following is equal to d?

Given y=a(x−2)(x+4). In the given quadratic equation, aa is a nonzero constant. The graph of the equation in the xy-plane is a parabola with vertex (c,d). Which of the following is equal to d?


  1. A
    -9a
  2. B
    -8a
  3. C
    -5a
  4. D
    -2a 

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    Solution:

    The parabola with equation y=a(x−2)(x+4), crosses x axis at the points (−4,0) and (2,0). 
    The x coordinate of the vertex of the parabola is halfway between the x coordinates of (−4,0) and (2,0). 
    Therefore, the x coordinate of the vertex is  2−4+2​=−1
    This is the value of c.We will find the y coordinate of the vertex, substitute −1 for x in y=a(x−2)(x+4):
    y=a(x−2)(x+4)=a(−1−2)(−1+4)=a(−3)(3)= −9a
    Hence, Option (1) is the correct answer.
     
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