MathematicsHow do you factor 2t2+7t+3 ?

How do you factor 2t2+7t+3 ?

A
t=-3, t= $\frac{- 1}{2}$
B
t=4, t=2
C
t=-4, t=-1
D
t=-2, t=4

Solution:

2t2+7t+3
         2t2+2t+t+3
2t(t+3)+1(t+3)
(t+3)(2t+1)
  By zero theorem
  (t+3)(2t+1)=0
   t=-3 , t=

\frac{- 1}{2}

So, option 1 is correct

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