How do you solve the equation x²=4x+1=0 by completing the square? - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

⇒

x^{2} - 4 x + 1 = 0

⇒

x^{2} - 2 \times 2 x + 1 + 4 - 4 = 0

⇒

{(x - 2)}^{2} = 3

\Rightarrow x - 2 = \pm \sqrt{3}

⇒

x = \sqrt{3} + 2

⇒

x = (2 + \sqrt{3}), (2 - \sqrt{3})

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