‘I’ is the perpendicular bisector of side BC of △ABC meeting the circumference of the triangle of M opposite to A then - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

A
∠MBC=∠MCB
B
∠BCM=∠BAM
C
∠CMB=∠CAM
D
∠BAM=∠CAM

Solution:

An arc in a circle subtends equal angles anywhere on the circumference.
BM is the chord.
∠BCM=∠BAM
Hence, option 2) is correct.
1) ∠MBC=∠MCB
∠MBC is subtended at the arc MC and the angle ∠MCB is subtended at the arc BM.
For the property, the angles should be subtended at the same arc.
Therefore, option 1) is incorrect.
3) ∠CMB=∠CAM
∠CMB is subtended at the arc BC and the angle ∠CAM is subtended at the arc CM.
For the property, the angles should be subtended at the same arc.
Therefore, option 3) is incorrect.
4) ∠BAM=∠CAM
∠BAM is subtended at the arc BM and the angle ∠CAM is subtended at the arc CM.
For the property, the angles should be subtended at the same arc.
Therefore, option 4) is incorrect.
So, Option 2 is correct.

Solution:

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