MathematicsIf π‘π‘œπ‘  (Ξ± + Ξ²) = 0, then 𝑠𝑖𝑛 (Ξ± βˆ’ Ξ²) can be reduced to

If π‘π‘œπ‘  (Ξ± + Ξ²) = 0, then 𝑠𝑖𝑛 (Ξ± βˆ’ Ξ²) can be reduced to

  1. A

    π‘π‘œπ‘  Ξ²

  2. B

    π‘π‘œπ‘  2Ξ²

  3. C

    𝑠𝑖𝑛 Ξ±

  4. D

    𝑠𝑖𝑛 2Ξ±

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    Solution:

    We have been given that π‘π‘œπ‘  (Ξ± + Ξ²) = 0

    We know that π‘π‘œπ‘  90Β° = 0

    β‡’ π‘π‘œπ‘  (Ξ± + Ξ²) = π‘π‘œπ‘  90Β°

    β‡’ Ξ± + Ξ² = 90Β°

    β‡’ Ξ± = 90Β° βˆ’ Ξ²

    Substituting the value of Ξ± from the above equation, we get 

    Now, 𝑠𝑖𝑛 (Ξ± βˆ’ Ξ²) = 𝑠𝑖𝑛 (90Β° βˆ’ Ξ² βˆ’ Ξ²)

    β‡’ 𝑠𝑖𝑛 (Ξ± βˆ’ Ξ²) = 𝑠𝑖𝑛 (90Β° βˆ’ 2Ξ²)

    We know that, for any angle ΞΈ, 𝑠𝑖𝑛 (90Β° βˆ’ ΞΈ) = π‘π‘œπ‘  ΞΈ 

    Therefore we can say that, 𝑠𝑖𝑛 (90Β° βˆ’ 2Ξ²) = π‘π‘œπ‘  2Ξ² 

    Hence, here 𝑠𝑖𝑛 (Ξ± βˆ’ Ξ²) can be reduced to π‘π‘œπ‘  2Ξ².

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