MathematicsIf A is a skew-symmetric matrix of order 2 and B, Carematrices 1    42    9 and  9    −4−2    1 respectively. ThenA3BC+A5B2C2+A7B3C3+…+A2n+1BnCn, is

If A is a skew-symmetric matrix of order 2 and B, Care

matrices 1    42    9 and  9    42    1 respectively. Then

A3BC+A5B2C2+A7B3C3++A2n+1BnCn, is

  1. A

    a symmetric matrix

  2. B

    a skew-symmetric matrix

  3. C

    an identity matrix

  4. D

    none of these

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    Solution:

    We observed that BC=I=CB 

    BnCn=CnBn=I for all nN

    Let X=A3BC+A5B2C2+A7B3C3++A2n+1BnCn. Then

    X=A3I+A5I+A7I++A2n+1I

        X=A3+A5+A7++A2n+1    XT=A3+A5+A7++A2n+1T    XT=A3T+A5T+A7T++A2n+1T    XT=AT3+AT5+AT7++AT2n+1    XT=(A)3+(A)5+(A)7++(A)2n+1AT=A    XT=XX is a skew-symmetric matrix. 

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