If A is a square matrix of order 3 then |Adj(AdjA2)|=

If A is a square matrix of order 3 then $| A d j (A d j A^{2}) | =$

A
${| A |}^{2}$
B
${| A |}^{4}$
C
${| A |}^{8}$
D
${| A |}^{16}$

Solution:

$| A d j {(A d j A)}^{2} | = {| A^{2} |}^{{(n - 1)}^{2}} = {| A |}^{8}$

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