Solution:
Area of Shaded region = 2 × Area of segment BC + Area of the circle with diameter DO
Since, DO=OC=BO=AO=7cm
∴ Area of segment BC = Area of quadrant BOC − Area of △ BOC
= cm2
Area of the circle with diameter DO = π × 3.5 × 3.5 = 38.5 cm2.
Area of Shaded region = 2 × 14 + 38.5 = 66.5 cm2.