If any four numbers are selected and they are multiplied, then the probability that the last digit will 1,3,5 or 7 is

If any four numbers are selected and they are multiplied, then the probability that the last digit will 1,3,5 or 7 is

A
4/625
B
8/625
C
16/625
D
None of these

Solution:

$The total number of digits in any number at the units place is 10 . ∴ n (S) = 10$

Digit in the units place of the product is 1 or 3 or 5 or 7

If the units place digit in the selected numbers must be 1 or 3 or 5 or 7

$n (E) = 4$

P(E) $= {(\frac{4}{10})}^{4} = \frac{16}{625}$

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