If n € N, n > 1, then value of  E=a−nC1(a−1)+nC2(a−2)+…….+(−1)n(a−n)nCn is                                                

If n € N, n > 1, then value of  

E=anC1(a1)+nC2(a2)+....+(1)n(an)nCn is                                                

  1. A

    α

  2. B

    0

  3. C

    α 2

  4. D

    2n

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    Solution:

    Given equation can be rewritten as

    E=a nC0nC1+nC2+(1)n nCn+ nC1(2) nC2+(3) nC3+(1)n(n) nCn

    E=0+0=0           by properties

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