Search for: MathematicsIf pr = 2 (q + s) then among the equations x2+px+q = 0 and x2 + rx + s = 0 If pr = 2 (q + s) then among the equations x2+px+q = 0 and x2 + rx + s = 0 Aboth have real rootsBboth have imaginary rootsCat least one has real rootsDat least one has imaginary roots Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:Δ1+Δ2=p2+r2−4(q+s)=p2+r2−2pr =(p−r)2≥0⇒at least one is+ve Related content Area of Square Area of Isosceles Triangle Pythagoras Theorem Triangle Formula Perimeter of Triangle Formula Area Formulae Volume of Cone Formula Matrices and Determinants_mathematics Critical Points Solved Examples Type of relations_mathematics