MathematicsIf pr = 2 (q + s) then among the equations x2+px+q = 0 and x2 + rx + s = 0

If pr = 2 (q + s) then among the equations x²+px+q = 0 and x² + rx + s = 0

A
both have real roots
B
both have imaginary roots
C
at least one has real roots
D
at least one has imaginary roots

Solution:

$\begin{aligned} Δ_{1} + Δ_{2} & = p^{2} + r^{2} - 4 (q + s) = p^{2} + r^{2} - 2 pr \\ = (p - r)^{2} \geq 0 \Rightarrow at least one is + ve \end{aligned}$

Related content

Distance Formula

Perimeter of Rectangle

Area of Square

Area of Isosceles Triangle

Pythagoras Theorem

Triangle Formulae

Volume of Cylinder

Perimeter of Triangle Formula

Area Formulae

Volume Formulae