If sin Y=X sin (a + y), then dydx is equal to 

If sin Y=X sin (a + y), then dydx is equal to 

  1. A

    sinasin2(a+y)

  2. B

    sin2(a+y)sina

  3. C

    sinasin2(a+v)

  4. D

    sin2(ay)sina

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    Solution:

    siny=xsin(a+y)

     x=sinysin(a+y)

    On differentiating  w.r.t.y, we get

    dxdy=sin(a+y)cosysinycos(a+y)sin2(a+y) dxdy=sinasin2(a+y)dydx=sin2(a+y)sina

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