If sin α and cos α are the roots of the equation ax2 +bx+c=0, then

A
$a^{2} - b^{2} + 2 ac = 0$
B
$(a - c)^{2} = b^{2} + c^{2}$
C
$a^{2} + b^{2} - 2 ac = 0$
D
$a^{2} + b^{2} + 2 ac = 0$

Solution:

. Since, sin $α$ and cos $α$ are the roots of the equation ax²+ bx+ c=0, then,
$\sin α + \cos α = - \frac{b}{a} and \sin αcos α = \frac{c}{a}$
To eliminate $α$ we have
$1 = \sin^{2} α + \cos^{2} α$
$\begin{array}{ll} \Rightarrow 1 = (\sin α + \cos α)^{2} - 2 \sin αcos α \\ \Rightarrow 1 = \frac{b^{2}}{a^{2}} - \frac{2 c}{a} \\ \Rightarrow a^{2} - b^{2} + 2 ac = 0 \end{array}$

If sin $α$ and cos $α$ are the roots of the equation ax² +bx+c=0, then

Solution:

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