If sum of the coefficients in the expansion 2×2−3cx+c2)17 is zero, then c is equal to

# If sum of the coefficients in the expansion $\left(2{x}^{2}-3cx+{c}^{2}{\right)}^{17}$ is zero, then $c$ is equal to

1. A

2, 3

2. B

1, 2

3. C

1, 3

4. D

2, – 1

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### Solution:

Sum of the coefficients $={\left(2-3c+{c}^{2}\right)}^{17}$

We are given ${\left(2-3c+{c}^{2}\right)}^{17}=0$

$⇒{c}^{2}-3c+2=0⇒c=1,2$

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