If the coordinates of the vertices of a ∆ABC are A(- 1, 3, 2), B(2, 3, 5) and C(9, b, – 2), then ∠ A isequal to

If the coordinates of the vertices of a ABC are A(- 1, 3, 2), B(2, 3, 5) and C(9, b, - 2), then  A is
equal to

  1. A

    45o

  2. B

    60o

  3. C

    90o

  4. D

    30o

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    Solution:

    Vertices of ABC are A(-1 ,3,2), B(2, 3, 5) and c(3, 5, -2). 

    AB=9+0+9=18

    CA=16+4+16=6and  BC=1+4+49=54

     AB2+CA2=BC2

    ABC is right angled triangle at A. 

    A=90o

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