Search for: If the last term in the binomial expansion of 21/3−12n is 135/3log38, the the 5th term from the begging is If the last term in the binomial expansion of 21/3−12n is 135/3log38, the the 5th term from the begging is A210B420C105DNone of these Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution: Last term of 21/3−12n is Tn+1=nCn21/3n−n−12n=nCn(−1)n12n/2=(−1)n2n/2Also, we have135/3log38=3−(5/3)log323=2−5 Thus, (−1)n2n/2=2−5⇒ (−1)n2n/2=(−1)1025⇒ n2=5⇒n=10Now T5=T4+1=10C421/310−4−124=10!4!6!21/36(−1)42−1/24=210(2)2(1)2−2=210 Related content Test your English Vocabulary CUET Exam Dates 2024 – Application Form, Fees, Eligibility CBSE Class 12 IP Answer Key 2024,Informatics Practices Paper Solution For SET 1, 2, 3, 4 CUET UG Cut Off 2024, Category, Universities and Colleges Wise Expected Cut Off Modal Verbs Helping Verbs Letter To Your Friend About Your School Trip Action Verbs CUET 2024 – List of Colleges and Participating Universities Accepting CUET Exam Score SRMJEEE Online Test Series – Practice Papers