If the line 3x+4y−24=0 intersects the x-axis at the point A and the y-axis at the point  B, then thein center of( the triangle OAB where O is the origin, is

If the line 3x+4y24=0 intersects the x-axis at the point A and the y-axis at the point  B, then the

in center of( the triangle OAB where O is the origin, is

  1. A

    (4, 4)

  2. B

    (2, 2)

  3. C

    (3, 4)

  4. D

    (4, 3)

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    Solution:

    Let (h,k) be the

    incentre of the OAB

    From figure, it is clear that

    h=k

    Now, perpendicular distance

    From (h,h) to the line 3x+4y=2

    is  the radius 

    h