If the mean of the following frequency distribution is 5, then $b =$

$\begin{array}{l}{x}_i\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}:\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em} 3\hspace{0.25em} \hspace{0.25em}\hspace{0.25em}\hspace{0.25em}5 \hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}7 \hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}4\\ f_i\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}:\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}2 \hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}a \hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}5 \hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}b\end{array}$
 

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